The direction cosines of the perpendicular from the origin to the plane 3x−y+4z=5 are
A
4,−1,3
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B
3,−1,4
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C
3√26,−1√26,4√26
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D
4√26,−1√26,3√26
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Solution
The correct option is C3√26,−1√26,4√26 The direction ratios of the perpendicular from the origin to the plane 3x−y+4z=5 are (3,−1,4) Therefore, direction cosines are (3√32+12+42,−1√32+12+42,4√32+12+42)=(3√26,−1√26,4√26) Ans: C