The direction of three forces 1 N, 2 N and 3 N acting at a point are parallel to the sides of an equilateral triangle taken in order. The magnitude of their resultant in newton upto 2 decimal places is
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Solution
Resultant force at the given point is →F=1^i−1^i−32^i+√3^j−3√32^j →F=−32^i−√32^j |→F|=√94+34=√124=√3N
Why this question?
Concept: This is a classic example that any number of vectors can be easily added after breaking them into components, and vectorially adding their respective components.