Question

The direction ratios of a vector are $2,-3,4$ . Find its direction cosines

Answer 1

Direction Ratios are $2,-3,4$.

Direction cosines.

$l=\frac{2}{\sqrt{2^2+(-3{)}^2+4^2}}=\frac{2}{\sqrt{29}}$

$m=\frac{-3}{\sqrt{2^2+(-3{)}^2+4^2}}=\frac{-3}{\sqrt{29}}$

$n=\frac{4}{\sqrt{2^2+(-3{)}^2+4^2}}=\frac{4}{\sqrt{29}}$