Question

The direction ratios of the line $6x-2=3y+1=2z-2$ are

• A. $\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}},\frac{1}{\sqrt{3}}$
• B. $\frac{1}{\sqrt{14}},\frac{2}{\sqrt{14}},\frac{3}{\sqrt{14}}$
• C. $1,2,3$
• D. None of these

Answer 1

Answer: (C)

$1,2,3$

$6x-2=3y+1=2x-2$

$6(x-\frac{2}{6})=3(y+\frac{1}{3})=2(x-\frac{2}{2})$

$\frac{(x-\frac{1}{3})}{1}=\frac{(y+\frac{1}{3})}{2}=\frac{(x-1)}{3}$

Line will be passing through the poits, $(\frac{1}{3},-\frac{1}{3},1)$

and parallel to the line having direction ratios is $1,2,3$

option $C$ will be the correct answer