The directional derivative f(x,y,z)=2x2+3y2+z2 at point P(2,1,3) in the direction of the vector →a=→i−→2k is
A
4√5
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B
−4√5
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C
√54
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D
−√54
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Solution
The correct option is B−4√5 f(x,y,z)=2x2+3y2+z2 ▽f=4x^i+6y^j+2z^k ▽f|(2,1,3)=8^i+6^j+6^k
and →a=^i−2^k
Directional Derivative: =▽f.^a =(8^i+6^j+6^k).(^i−2^k)√5 =8−12√5=−4√5