The directrices of a standard hyperbola x2a2 -y2b2 - 1are x - ae-

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The directric...

Question

The directrices of a standard hyperbola $\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1$
are $x = \pm \frac{a}{e} .$

True

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False

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Similar questions

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

\frac{\pm b^{2}}{a}

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1.

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

e

\frac{y^{2}}{b^{2}} - \frac{x^{2}}{a^{2}} = 1

e

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

f (e)

- \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1

\int_{1}^{3} f f f . . . . . f (e)      n t i m e s d e

\frac{x^{2}}{a^{2}} - \frac{y^{2}}{b^{2}} = 1

\frac{y^{2}}{b^{2}} - \frac{x^{2}}{a^{2}} = 1

e

e_{1}

\frac{1}{e^{2}} + \frac{1}{e_{1}^{2}} =

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