Question

The discrimiant of the quadratic equation $3\sqrt{3}{x}^2+10x+\sqrt{3}=0$ is

• A. $8$
• B. $64$
• C. $-\frac{1}{3\sqrt{3}}$
• D. $-\sqrt{3}$

Answer 1

Answer: (B)

$64$

Given equation is:

$3\sqrt{3}{x}^2+10x+\sqrt{3}=0$

$D=b^2-4ac$
$\therefore D=(10{)}^2-4(3\sqrt{3}\left)\right(\sqrt{3})$
$=100-36$
$=64$