Question

The discriminant of quadratic equation $3x^2-4x-1=0$ is _______.

• A. $0$
• B. $4$
• C. $12$
• D. $28$

Answer 1

Answer: (D)

$28$

Quadratic equation: $3x^2-4x-1=0$

Comparing the given equation with $a{x}^2+bx+c=0$

we have $a=3,b=-4,c=-1$

Now, discriminant

$D=b^2-4ac$

$=(-4{)}^2-4(3\left)\right(-1)$

$=16+12$

$=28$.