The discriminant of the quadratic equation 3 x 2-4 -3 x -4-0 is A- D -4B- D -2C- D -0D- D -96

The correct option is C D=0Given, 3x^2 4√(3)x+4=0 nbsp; Comparing the equation with ax^2+bx+c=0, we get a=3, b= 4√(3), c=4 We know the discriminant is D=b^2 ...

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Standard XII

Mathematics

Discriminant

The discrimin...

Question

The discriminant of the quadratic equation $3 x^{2} - 4 \sqrt{3} x + 4 = 0$ is

D = 4

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D = - 2

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D = 0

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D = 96

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Solution

The correct option is C $D = 0$
Given,
$3 x^{2} - 4 \sqrt{3} x + 4 = 0$
Comparing the equation with $a x^{2} + b x + c = 0$ , we get
$a = 3, b = - 4 \sqrt{3}, c = 4$
We know the discriminant is
$D = b^{2} - 4 a c \Rightarrow D = (- 4 \sqrt{3})^{2} - 4 \times 3 \times 4 ∴ D = 0$

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Discriminant

Standard XII Mathematics

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The discriminant of the quadratic equation 3x2−4√3x+4=0 is

The correct option is C D=0Given, 3x2−4√3x+4=0 Comparing the equation with ax2+bx+c=0, we get a=3,b=−4√3,c=4 We know the discriminant is D=b2−4ac⇒D=(−4√3)2−4×3×4∴D=0

The discriminant of the quadratic equation $3 x^{2} - 4 \sqrt{3} x + 4 = 0$ is

The correct option is C $D = 0$
Given,
$3 x^{2} - 4 \sqrt{3} x + 4 = 0$
Comparing the equation with $a x^{2} + b x + c = 0$ , we get
$a = 3, b = - 4 \sqrt{3}, c = 4$
We know the discriminant is
$D = b^{2} - 4 a c \Rightarrow D = (- 4 \sqrt{3})^{2} - 4 \times 3 \times 4 ∴ D = 0$