Question

The discriminant of the quadratic equation $3x^2-4\sqrt{3}x+4=0$ is

• A. $D=4$
• B. $D=-2$
• C. $D=0$
• D. $D=96$

Answer 1

The correct option is C $D=0$

Given,
$3x^2-4\sqrt{3}x+4=0$
Comparing the equation with $a{x}^2+bx+c=0$, we get
$a=3,b=-4\sqrt{3},c=4$
We know the discriminant is
$D=b^2-4ac\Rightarrow D=(-4\sqrt{3}{)}^2-4\times 3\times 4\therefore D=0$