Question

The discriminant value of equation $5x^2-6x+1=0$ is ...............

• A. $16$
• B. $\sqrt{56}$
• C. $4$
• D. $56$

Answer 1

The correct option is A $16$

The given equation is $5x^2-6x+1=0$ ........... $\left(i\right)$

General form of quadratic equation is given by $a{x}^2+bx+c=0$ ....... $\left(ii\right)$

Comparing equation $\left(i\right)$ with $\left(ii\right)$ we have,

$a=5,b=-6,c=1$

The discriminant $D$ is given by

$D=b^2-4ac={(-6)}^2-4\left(5\right)\left(1\right)=36-20=16$

$\therefore$ Discriminant value is $D=16$