The dispIacement of a body is given by $2 s = g t^{2}$ where g is a constant. The velocity of the body at any time t is:

g t

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{g t}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{g t^{2}}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{g t^{3}}{6}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $g t$

Given that:

$2 s = g t^{2}$

$s = \frac{1}{2} g t^{2}$

Comparing this with the equation:

$s = u t + \frac{1}{2} a t^{2}$

we get,

$u = 0 & a = g$

$v = u + a t = 0 + g t$

Suggest Corrections

Similar questions

Q. The displacement of a body is given by

s = \frac{1}{2} g t^{2}

, where

g

is acceleration due to gravity. The velocity of the body at any time

t

Q. A body undergoes a free fall. Taking downward direction as +ve

Y

direction and

Y_{o}

is the initial position,

Y

coordinate at any time

t

is given by

A body is dropped from a certain height at time $T = 0$ . It undergoes freefall and reaches the ground at time $T = t$ s. What is the expression for the height $h$ from which the body started its free fall?

Acceleration due to gravity is $g$ .

Q. The velocity of a body is given by the equation v

=

6 - 0.02t, where t is the time taken.
The body is undergoing:

Q. The displacement of a body at any time

t

after starting is given by

s = 15 t - 0.4 t^{2}

. Find the time when the velocity of the body will be

7 m s^{- 1}

Join BYJU'S Learning Program

The dispIacement of a body is given by 2s=gt2 where g is a constant. The velocity of the body at any time t is:

The correct option is A gt Given that: 2s=gt2 s=12gt2 Comparing this with the equation: s=ut+12at2 we get, u=0 & a=g v=u+at=0+gt

The dispIacement of a body is given by $2 s = g t^{2}$ where g is a constant. The velocity of the body at any time t is:

The correct option is A $g t$

Given that:

$2 s = g t^{2}$

$s = \frac{1}{2} g t^{2}$

Comparing this with the equation:

$s = u t + \frac{1}{2} a t^{2}$

we get,

$u = 0 & a = g$

$v = u + a t = 0 + g t$