Question

The displacement amplitude A of the waves received by the observer (in micrometeres)

Answer 1

The given displacement equation is $y=A\sin (15\pi x-6000\pi t)$
Comparing it with $y=A\sin (kx-wt)$
We get $k=15\pi$
Bulk modulus $B=1.6\times {10}^{5}N/m^2$
Pressure amplitude $P_o=24\pi Pa$
Displacement amplitude $A=\frac{P_o}{Bk}$
$\therefore$ $A=\frac{24\pi }{(1.6\times {10}^5)\left(15\pi \right)}={10}^{-5}m=10\mu m$