The displacement amplitude of particles of air of density 1-2 kg-m3 is 60-x A- - if intensity- frequency and speed of sound are 8 x 1o-6 w-m2- 5000Hz and 330m-s respectively- Find x -

The relation between the intensity of sound and the displacement amplitude is I = P^2 _0/2pv, #160; P_0 =√(2pvI) , #160; s_0 = P_0/Bk #160;=√(2pvI)/p ...

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Byju's Answer

Standard VIII

Physics

Introduction to Waves

The displacem...

Question

The displacement amplitude of particles of air of density $1.2 k g / m^{3}$ is $(60 + x) A^{\circ}$ , if intensity, frequency and speed of sound are $8 x 1 o^{- 6} w / m^{2}$ , 5000Hz and 330m/s respectively. Find x :

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Solution

The relation between the intensity of sound and the displacement amplitude is
$I = \frac{P_{0}^{2}}{2 p v}, P_{0} = \sqrt{2 p v I}, s_{0} = \frac{P_{0}}{B k} = \frac{\sqrt{2 p v I}}{p v^{2} 2 π f}, v = \sqrt{\frac{I}{p v 2}} = \frac{1}{π f}$
or, $s_{0} = 64 A^{\circ}$

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