The displacement at a point due to two waves are y1-sin500- tand y2 -2sin506- t- The result due to their superposition will be

Superimposed wave will be 6 beats per second #10; #10;Intensity relation between #160;maximum and minimum would be 9 #10; #10;f1 = 500 #10; #10;f ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Resultant Wave Equation

The displacem...

Question

The displacement at a point due to two waves are $y_{1} = s i n (500 π t) a n d y_{2} = 2 s i n (506 π t)$ . The result due to their superposition will be

Open in App

Solution

Suggest Corrections

Similar questions

y_{1} = 4 s i n (500 π t)

y_{2} = 2 s i n (506 π t)

y_{1} = 4 sin (500 π t - 25 x)

y_{2} = 2 sin (506 π t - 30 x)

(I_{m a x})

(I_{m i n})

y_{1} = 5 sin (w t - k x)

y_{2} = - 5 cos (w t - k x - 150^{o})

y_{1} = 5 s i n

y_{2}

150^{o}

y_{1} = 4 sin (500 π t - 25 x)

y_{2} = 2 sin (506 π t - 30 x)

(I_{m a x})

(I_{m i n})

Join BYJU'S Learning Program