The displacement in n th second of uniformly acelerated motion is given by S n th -u- a 2 2n-1 - This equation is dimensionally

The correct option is B correctSince: LS_n^th=L[u(n)+ 1/2an^2] L[u(n 1)+ 1/2a(n 1)^2] Hence dimensionally correct, as n has been cancelled out during calc ...

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Byju's Answer

Standard XII

Physics

Dimensional Analysis

The displacem...

Question

The displacement in $n^{t h}$ second of uniformly acelerated motion is given by $S_{n^{t h}} = u + \frac{a}{2} (2 n - 1)$ . This equation is dimensionally

correct

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not correct

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can be made correct by multiplying the right hand side of equation by n.

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can be made correct by dividing the left h and side of the equation by n.

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Solution

The correct option is B correct
Since:
$S_{n^{t h}} L = [u (n) + \frac{1}{2} a n^{2}] L - [u (n - 1) + \frac{1}{2} a (n - 1)^{2}] L$
Hence dimensionally correct, as n has been cancelled out during calculation .

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Similar questions

Q. In the equation

S_{n t h} = u + \frac{a}{2} (2 n - 1)

, the letters have their usual meanings. The dimensional formula of

S_{n t h}

Q. The displacement of a body at a particular second

(n)

is given by the expression

s_{n^{t h}} = u + \frac{a}{2} (2 n - 1)

. The dimensional formula of

s_{n^{t h}}

in this equation is

Q. The displacement of a body at a particular second n is given by the expression

S_{n^{t h}} = u + \frac{a}{2} (2 n - 1)

. The dimensional formula of

S_{n^{t h}}

in this equation is

Q. The displacement of a body at a particular second

(n)

is given by the expression

s_{n^{t h}} = u + \frac{a}{2} (2 n - 1)

. The dimensional formula of

s_{n^{t h}}

in this equation is

Q. Check the correctness of the relation

S_{n t h} = u + \frac{a}{2} (2 n - 1)

, where

u

is initial velocity,

a

is acceleration and

S_{n t h}

is the distance travelled by the body in

n t h

second.

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The displacement in nth second of uniformly acelerated motion is given by Snth=u+a2(2n−1). This equation is dimensionally

The correct option is B correctSince:SnthL=[u(n)+12an2]L−[u(n−1)+12a(n−1)2]LHence dimensionally correct, as n has been cancelled out during calculation .

The displacement in $n^{t h}$ second of uniformly acelerated motion is given by $S_{n^{t h}} = u + \frac{a}{2} (2 n - 1)$ . This equation is dimensionally

The correct option is B correct
Since:
$S_{n^{t h}} L = [u (n) + \frac{1}{2} a n^{2}] L - [u (n - 1) + \frac{1}{2} a (n - 1)^{2}] L$
Hence dimensionally correct, as n has been cancelled out during calculation .