Question

The displacement of a body is given to be proportional to the cube of time elapsed. If the accerlation is $xkt($where $k$ is proportionality constant$)$. Find $x$?

Answer 1

Given, $x\propto t^3$ or $x=k{t}^3$
Thus, $v=\frac{dx}{dt}=3k{t}^2$ and $a=\frac{dv}{dt}=6kt=xkt$, giving $x=6.$