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Second Law of Motion

The displacem...

Question

The displacement of a particle executing S.H.M is given by $x$ = $0.25 s i n 200 t$ in meters, the maximum speed of particle is:

50 m / s

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25 m / s

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200 m / s

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100 m / s

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Solution

The correct option is A $50 m / s$
$x = 0.25 s i n 200 t$
Speed, $v = \frac{d x}{d t} = 0.25 \times 200 c o s 200 t$
The maximum speed of particle $v_{m} = 50 m / s$
The correct option is A.

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