The displacement of a particle executing SHM at any instant t is x-7cos0-5 - t- The time taken by the particle in reaching from mean position to extreme position will be

A particle is executing S.H.M with the amplitude of 4 cm and period 12 s. The time taken by the particle in going from its mean position to a position of displacement equal to 2 cm is T1. The time taken from this displaced of 2 cm to reach the extreme position is T2. T1/T2 will be.

Q. A particle is executing SHM of periodic time T. The time taken by a particle in moving from mean position to half the maximum displacement is:

(sin

30^{o} = 0.5

)

Q. A particle executing SHM takes

4 s

to move from one extreme to another extreme position. Find the time period of the particle.

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The displacement of a particle executing SHM at any instant t is x=7cos0.5πt. The time taken by the particle in reaching from mean position to extreme position will be

The correct option is C 1sIt takes T4 seconds to go from mean to extreme position (2π in T, means π2 in T4)Here, ω=0.5π, thus T=2πω=4Thus, T4=1 s

The displacement of a particle executing SHM at any instant t is $x = 7 cos 0.5 π t$ . The time taken by the particle in reaching from mean position to extreme position will be

The correct option is C $1 s$
It takes $\frac{T}{4}$ seconds to go from mean to extreme position $(2 π in T, means \frac{π}{2} in \frac{T}{4})$
Here, $ω = 0.5 π$ , thus $T = \frac{2 π}{ω} = 4$
Thus $, \frac{T}{4} = 1 s$