Question

The displacement of a particle executing simple harmonic motion at any instant t is $x=3\cos 2\pi t$. The acceleration produced in the particle will be:

• A. $-12{\pi }^2\sin 2\pi t$
• B. $-12{\pi }^2\cos 2\pi t$
• C. $12\pi \cos 2\pi t$
• D. $Zero$

Answer 1

The correct option is B $-12{\pi }^2\cos 2\pi t$

$a=-{\omega }^{2}x=-\left(2\pi {)}^2\right(3cos2\pi t)=-12{\pi }^{2}cos2\pi t$