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Question

The displacement of a particle in simple harmonic motion in one time period is:

A
A
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B
2A
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C
4A
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D
Zero
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Solution

The correct option is D Zero
Let position of the particle at any instant y=Asin(wt+ϕ)
y=Asin[2πTt+ϕ] where w=2πT
Position of the particle after one time period yT=Asin[2πT(t+T)+ϕ]
yT=Asin[2πTt+2π+ϕ]
yT=Asin[2πTt+ϕ]
Thus net displacement of the particle in one time period s=yTy=0


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