The displacement of a particle is given by r-A-i-cos- t-j-sin- t-The motion of the particle issimple harmonic-on a straight line-on a circle-with constant acceleration-

The correct option is C on a circle The position vector is given as a function of time as: r=A(cos ω tî+sin ω tĵ) Which means the particle is at a constant dis ...

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Standard XII

Physics

Relating Circular Motion to SHM

The displacem...

Question

The displacement of a particle is given by $\to r = A (\to i c o s ω t + \to j s i n ω t)$ The motion of the particle is

simple harmonic

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on a straight line

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on a circle

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with constant acceleration

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Solution

The correct option is C
on a circle

The position vector is given as a function of time as:

$\to r = A (c o s ω t^i + s i n ω t^j)$

Which means the particle is at a constant distance A from the origin at all times t. Hence its circular motion

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Similar questions

Q. The displacement of a particle is given by

\vec{r} = A (\vec{i} \cos ω t + \vec{j} \sin ω t) .

The motion of the particle is
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(b) on a straight line
(c) on a circle
(d) with constant acceleration

The displacement of a particle is given by $\to r = A (\to i c o s ω t + \to j s i n ω t)$ The motion of the particle is

Q. The displacement of a particle is given by

\vec{r} = A (\vec{i} \cos ω t + \vec{j} \sin ω t) .

The motion of the particle is
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(b) on a straight line
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Q. The displacement of a particle is given by

\to r = A (\to i cos ω t + \to j sin ω t)

. The motion of the particle is :

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The displacement of a particle is given by →r=A(→i cos ωt+→j sin ωt)The motion of the particle is

The correct option is C on a circle The position vector is given as a function of time as: →r=A(cos ωt^i+sin ωt^j) Which means the particle is at a constant distance A from the origin at all times t. Hence its circular motion

The displacement of a particle is given by $\to r = A (\to i c o s ω t + \to j s i n ω t)$ The motion of the particle is

The correct option is C
on a circle

The position vector is given as a function of time as:

$\to r = A (c o s ω t^i + s i n ω t^j)$

Which means the particle is at a constant distance A from the origin at all times t. Hence its circular motion