The displacement of a particle is given by r-Ai cos - t-j sin - tThe motion of the particle is

The position vector is given as a function of time as: r=A(cos ω tî+sin ω tĵ) Which means the particle is at a constant distance A from the origin at all time ...

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Standard VII

Physics

Uniform Motion

The displacem...

Question

The displacement of a particle is given by $\to r = A (\to i c o s ω t + \to j s i n ω t)$ The motion of the particle is

simple harmonic

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on a straight line

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on a circle

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with constant acceleration

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Solution

The correct option is C
on a circle

The position vector is given as a function of time as:

$\to r = A (c o s ω t^i + s i n ω t^j)$

Which means the particle is at a constant distance A from the origin at all times t. Hence its circular motion

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The displacement of a particle is given by →r=A(→i cos ωt+→j sin ωt)The motion of the particle is

The correct option is C on a circle The position vector is given as a function of time as: →r=A(cos ωt^i+sin ωt^j) Which means the particle is at a constant distance A from the origin at all times t. Hence its circular motion

The displacement of a particle is given by $\to r = A (\to i c o s ω t + \to j s i n ω t)$ The motion of the particle is

The correct option is C
on a circle

The position vector is given as a function of time as:

$\to r = A (c o s ω t^i + s i n ω t^j)$

Which means the particle is at a constant distance A from the origin at all times t. Hence its circular motion