The displacement of a particle is given by $x = 4 t^{2} + 2 t$ in $m$ . Its instantaneous velocity at $2 s$ is

16 m/s

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18 m/s

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22 m/s

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36 m/s

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Solution

The correct option is B $18 m/s$
Instantaneous velocity
$v = {(\frac{d x}{d t})}_{t = 2 s} = {(\frac{d (4 t^{2} + 2 t)}{d t})}_{t = 2 s} = 8 t + 2 |_{t = 2 s}$
$v = 16 + 2 = 18 m/s$

Suggest Corrections

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