The displacement of a particle is represented by the equation y -sin 3- t- The motion isA- non-periodicB- periodic but not simple harmonicC- simple harmonic with period - - -D- simple harmonic with period 2 - - -

The correct option is B periodic but not simple harmonicGiven, y=sin^3 ω t=14[3 sinω t sin 3 ω t] As this motion is not represented by simple harmonic function ...

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Standard XII

Physics

Periodic Motion

The displacem...

Question

The displacement of a particle is represented by the equation $y = {sin}^{3} ω t$ . The motion is

non-periodic

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periodic but not simple harmonic

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simple harmonic with period

2 π / ω

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simple harmonic with period

π / ω

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Solution

The correct option is B periodic but not simple harmonic
Given, $y = {sin}^{3} ω t = \frac{1}{4} [3 sin ω t - sin 3 ω t]$
As this motion is not represented by simple harmonic function, hence it is not SHM. As this motion involves sine and cosine functions, hence it is periodic motion.

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Periodic Motion

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The displacement of a particle is represented by the equation y=sin3ωt. The motion is

The correct option is B periodic but not simple harmonicGiven, y=sin3ωt=14[3sinωt−sin3ωt] As this motion is not represented by simple harmonic function, hence it is not SHM. As this motion involves sine and cosine functions, hence it is periodic motion.

The displacement of a particle is represented by the equation $y = {sin}^{3} ω t$ . The motion is

The correct option is B periodic but not simple harmonic
Given, $y = {sin}^{3} ω t = \frac{1}{4} [3 sin ω t - sin 3 ω t]$
As this motion is not represented by simple harmonic function, hence it is not SHM. As this motion involves sine and cosine functions, hence it is periodic motion.