Question

The displacement of a particle is represented by the equation $y={\sin }^3\omega t$. The motion is

• A. non-periodic
• B. periodic but not simple harmonic
• C. simple harmonic with period $2\pi /\omega$
• D. simple harmonic with period $\pi /\omega$

Answer 1

The correct option is B periodic but not simple harmonic

Given, $y={\sin }^3\omega t=\frac{1}{4}[3\sin \omega t-\sin 3\omega t]$
As this motion is not represented by simple harmonic function, hence it is not SHM. As this motion involves sine and cosine functions, hence it is periodic motion.