Question

The displacement of a particle moving along $x$ axis is given by $X=(4t^2+3t+7)\mu$. Calculate instantaneous velocity and instantaneous acceleration at $t=2S$.

Answer 1

X = $4t^2$ + 3t + 7

V = $\frac{dx}{dt}$ = instantaneous velocity

V = 8t + 3

at t = 2

v = 19 m/s

a = $\frac{dv}{dt}$ instantaneous accelesation

a= 8 (constant)

at t = 2

$a=8m/s^2$