The displacement of a particle moving in S-H-M- at any instant is given by y - a sin- t- The acceleration after time t - T -4 is where T is the time period-MP PET 1984-A- aoB- -a-C- a -2D- - a -2

The correct option is D aω2 a ω^2 when it is at one extreme point. ...

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Standard XII

Physics

Dimensional Analysis

The displacem...

Question

The displacement of a particle moving in S.H.M. at any instant is given by y = a sin $ω t$ . The acceleration after time $t = \frac{T}{4}$ is (where T is the time period) [MP PET 1984]

aω

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-aω

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aω²

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-aω²

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Solution

The correct option is D. -aω²
We know that,
T=2π/ω, thus T/4=π/2ω
Thus, x=asinωt=asinω(π/2ω)=asinπ/2=a
Thus, acceleration = $- ω^{2} x = - a ω^{2}$ when it is at one extreme point.

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The displacement of a particle moving in S.H.M. at any instant is given by y = a sin ωt . The acceleration after time t=T4 is (where T is the time period) [MP PET 1984]

The correct option is D. -aω2We know that,T=2π/ω, thus T/4=π/2ωThus, x=asinωt=asinω(π/2ω)=asinπ/2=aThus, acceleration = −ω2x=−aω2 when it is at one extreme point.

The displacement of a particle moving in S.H.M. at any instant is given by y = a sin $ω t$ . The acceleration after time $t = \frac{T}{4}$ is (where T is the time period) [MP PET 1984]

The correct option is D. -aω²
We know that,
T=2π/ω, thus T/4=π/2ω
Thus, x=asinωt=asinω(π/2ω)=asinπ/2=a
Thus, acceleration = $- ω^{2} x = - a ω^{2}$ when it is at one extreme point.