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Question
The displacement of a particle varies with time as x=12 sin ω t−16 sin3 ω t (in cm). If its motion is S.H.M., then its maximum acceleration is
The displacement of a particle varies with time as x=12 sin ω t−16 sin3 ω t (in cm). If its motion is S.H.M., then its maximum acceleration is
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Solution
The correct option is B 36ω2
x = 12 sin ω t−16 sin3ω t=4[3 sin ω t−4 sin3ω t]
= 4[ sin 3 ω t] (By using sin 3 θ=3 sin θ−4 sin3 θ
∴Maximum acceleration Amax=(3 ω)2×4=36 ω2
36ω2
x = 12 sin ω t−16 sin3ω t=4[3 sin ω t−4 sin3ω t]
= 4[ sin 3 ω t] (By using sin 3 θ=3 sin θ−4 sin3 θ
∴Maximum acceleration Amax=(3 ω)2×4=36 ω2