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Question

The displacement of a particle varies with time t as: s=αt2βt3. Determine the time (t) at which acceleration of the particle becomes 0.

A
α3β
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B
αβ
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C
3βα
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D
2α3β
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Solution

The correct option is A α3β
Given,
s=αt2βt3
Differentiating s w.r.t t we get,
Velocity, v=dsdt=2αt3βt2
Differentiating v w.r.t t we get,
Acceleration, a=dvdt=2α6βt
As a=0, we get
2α6βt=0t=α3β

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