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Question

The displacement of an object attached to a spring and executing simple harmonic motion is given by x=2×102cosπt metres. The time at which the maximum speed first occurs is -

A
0.5 s
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B
0.75 s
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C
0.125 s
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D
0.25 s
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Solution

The correct option is B 0.5 s
Given, displacement x=2×102cosπt
The magnitude of velocity , v=|dxdt|=2π×102sinπt
So, the velocity will be maximum when sinπt=1 where πt=π2,3π2,..
So for first maximum, πt=π2 or t=0.5s

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