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Question

The displacement of the particle is given by x=3t3+6t2+2t+5 in m. The instantaneous speed of the particle at 4 sec is

A
194 m/s
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B
180 m/s
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C
200 m/s
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D
156 m/s
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Solution

The correct option is A 194 m/s
As we know that the instantaneous speed of the particle is given by
dxdt=d(3t3+6t2+2t+5)dt
v=9t2+12t+2
So, v|@t=4 sec=9×42+12×4+2=194 m/s

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