The displacement s of a particle is proportional to the first power of time t- i-e- s - t - then the acceleration of the particle isA- InfiniteB- A large finite valueC- ZeroD- A small finite value

The correct option is C ZeroLet s=kt+c Differentiating s twice to get acceleration, we see that d^2sdt^2=0 ∴ nbsp;Acceleration comes out to be zero. ...

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Standard XII

Physics

Uniform and Non Uniform

The displacem...

Question

The displacement ( $s$ ) of a particle is proportional to the first power of time $t$ , i.e., $s \propto t$ ; then the acceleration of the particle is

Infinite

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Zero

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A small finite value

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A large finite value

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Solution

The correct option is B Zero
Let $s = k t + c$
Differentiating $s$ twice to get acceleration, we see that
$\frac{d^{2} s}{d t^{2}} = 0$
$∴$ Acceleration comes out to be zero.

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The displacement (s) of a particle is proportional to the first power of time t, i.e., s∝t; then the acceleration of the particle is

The correct option is B ZeroLet s=kt+c Differentiating s twice to get acceleration, we see that d2sdt2=0 ∴ Acceleration comes out to be zero.

The displacement ( $s$ ) of a particle is proportional to the first power of time $t$ , i.e., $s \propto t$ ; then the acceleration of the particle is

The correct option is B Zero
Let $s = k t + c$
Differentiating $s$ twice to get acceleration, we see that
$\frac{d^{2} s}{d t^{2}} = 0$
$∴$ Acceleration comes out to be zero.