The displacement time graph for the particles A and B are straight lines inclined at angles $30$ degree and $40$ degree with the time axis. What is the ratio of the velocities of A and B?

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Solution

We know that,

Velocityis equal to the Slope of the line formed in displacement v/s time graph $= t a n θ$

$V_{a} : V_{b} = t a n 30^{0} : t a n 45^{0} = (\frac{1}{\sqrt{3}}) : 1 = 1 : \sqrt{3}$

Ratio of velocities of $A : B$ is $1 : \sqrt{3}$

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The displacement-time graph for two particles A and B are straight lines inclined at angles of $30^{\circ}$ and $60^{\circ}$ with the time axis. The ratio of velocities of $V_{A}$ : $V_{B}$ is

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The displacement time graph for the particles A and B are straight lines inclined at angles 30 degree and 40 degree with the time axis. What is the ratio of the velocities of A and B?

We know that,Velocityis equal to the Slope of the line formed in displacement v/s time graph =tanθVa:Vb=tan300:tan450=(1√3):1=1:√3Ratio of velocities of A:B is 1:√3

The displacement time graph for the particles A and B are straight lines inclined at angles $30$ degree and $40$ degree with the time axis. What is the ratio of the velocities of A and B?

We know that,

Velocityis equal to the Slope of the line formed in displacement v/s time graph $= t a n θ$

$V_{a} : V_{b} = t a n 30^{0} : t a n 45^{0} = (\frac{1}{\sqrt{3}}) : 1 = 1 : \sqrt{3}$

Ratio of velocities of $A : B$ is $1 : \sqrt{3}$