The displacement-time graph for two particles A and B are straight lines inclined at angles of 30- and 60- with the time axis- The ratio of velocities of V A - V B isA- 1- 2B- 1- -3C- -3- 1D- 1- 3

The correct option is D 1:3 The slope is given by tan θ. Therefore, V_A/V_B = tan θ_A/tan θ_B = tan 30^∘/tan 60^∘ = 1/√(3)/√(3) = 1/3 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Position Time Graph

The displacem...

Question

The displacement-time graph for two particles A and B are straight lines inclined at angles of $30^{\circ}$ and $60^{\circ}$ with the time axis. The ratio of velocities of $V_{A}$ : $V_{B}$ is

1:2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1:3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D
1:3

The slope is given by $t a n θ$ . Therefore,

$\frac{V_{A}}{V_{B}} = \frac{t a n θ_{A}}{t a n θ_{B}} = \frac{t a n 30^{\circ}}{t a n 60^{\circ}} = \frac{\frac{1}{\sqrt{3}}}{\sqrt{3}} = \frac{1}{3}$

Suggest Corrections

Similar questions

The displacement-time graph for two particles A and B are straight lines inclined at angles of $30^{\circ}$ and $60^{\circ}$ with the time axis. The ratio of velocities of $V_{A}$ : $V_{B}$ is

Q. The displacement time graph for two particles

A

and

B

are straight lines inclined at angles of

30^{\circ}

and

60^{\circ}

respectively with the time axis. The ratio

V_{A} ∶ V_{B}

Q. The displacement time graph for two particles

A

and

B

are straight lines inclined at angles of

30^{\circ}

and

60^{\circ}

with the time axis. The ratio of velocities of

V_{A} : V_{B}

Q. If the displacement-time graph for the two particles A and B are straight lines inclined at angles of

30^{0}

and

60^{0}

with the time axis, then ratio of the velocities

v_{A} : v_{B}

will be

Q. The displacement time graph for two particles

A

and

B

are straight lines inclined at angles of

30^{\circ}

and

60^{\circ}

respectively with the time axis. The ratio

V_{A} ∶ V_{B}

Join BYJU'S Learning Program

The displacement-time graph for two particles A and B are straight lines inclined at angles of 30∘ and 60∘ with the time axis. The ratio of velocities of VA : VB is

The correct option is D 1:3 The slope is given by tan θ. Therefore, VAVB=tanθAtanθB=tan30∘tan60∘=1√3√3=13

The displacement-time graph for two particles A and B are straight lines inclined at angles of $30^{\circ}$ and $60^{\circ}$ with the time axis. The ratio of velocities of $V_{A}$ : $V_{B}$ is

The correct option is D
1:3

The slope is given by $t a n θ$ . Therefore,

$\frac{V_{A}}{V_{B}} = \frac{t a n θ_{A}}{t a n θ_{B}} = \frac{t a n 30^{\circ}}{t a n 60^{\circ}} = \frac{\frac{1}{\sqrt{3}}}{\sqrt{3}} = \frac{1}{3}$