Question

The displacement-time graph of a particle moving along a straight line is shown in the figure. The acceleration of the particle is:

• A. $0m{s}^{-2}$
• B. $4m{s}^{-2}$
• C. $8m{s}^{-2}$
• D. $12m{s}^{-2}$

Answer 1

The correct option is C $8m{s}^{-2}$

$x=$ $4t^2$
$v=$ $\frac{dx}{dt}=8t$
Hence, velocity-time graph is a straight line having slope i.e. $tan\theta =8$
$a=\frac{dv}{dt}=8m/s^2$
Hence, acceleration is constant throughout and is equal to $8m/s^2$.