The displacement-time graph of a particle moving along the x-axis is shown below. The average velocity of the particle for the time interval (0−3T2)s is
A
4x3T
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B
xT
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C
0
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D
2x3T
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Solution
The correct option is C 0 Let the initial position of the particle at t = 0 be xi and the final position of the particle at t=3T2 be xf.
According to the graph, xi=xf=x
Net displacement =xf–xi=x–x=0m Averagevelocity=Netdisplacementtimetaken=03T2−0
⇒ Average velocity = 0 m/s
Hence, the correct answer is option (c).