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Question

The displacement-time(xt) graph of a particle undergoing simple harmonic motion is shown below. The acceleration of the particle at t=43s is


A
332π2 cm/s2
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B
π232 cm/s2
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C
π232 cm/s2
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D
332π2 cm/s2
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Solution

The correct option is D 332π2 cm/s2
From given graph, amplitude (A)=1 cm
Time period (T)=8 s
ω=2π8=π4 rad/s
Dispalcement of the particle, x=Asinωt
Acceleration , a=ω2A sin ωt
at t=43 s,
a=π216×1×sin (π4×43)
=π216sin(π3)
=332π2cm/s2

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