Question

The displacement x (in metre) of a particle in, simple harmonic motion is related to time t (in seconds) as

x = 0.01 cos $(\pi t+\frac{\pi }{4})$

The frequency of the motion will be

• A. 0.5 Hz
• B. 1.0 Hz
• C.
• D. πHz

Answer 1

The correct option is A

0.5 Hz

Comparing given equation with standard equation,

x = a cos $(\omega t+\varphi )$, We get , a = 0.01 and $\omega =\pi$

$\Rightarrow 2\pi n=\pi \Rightarrow n=0.5hz$