The displacement x (in metres) of a particle is simple harmonic motion is related to time t (in seconds) as x = $0.01 c o s (π t + \frac{π}{4})$ What is the frequency of the motion?

0.5 Hz

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1.0 Hz

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\frac{π}{2}

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π H Z

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Solution

The correct option is A 0.5 Hz
The coefficient of time t in the argument of the cosine function gives the angular frequency ω of the motion.
Hence $ω = π o r 2 π v = π o r v = \frac{1}{2} = 0.5 H_{Z}$
Hence the correct choice is (a)

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