The displacement x of a body varies with time t as x - 23 t2 - 16t - 2- In what time that body comes to rest- x is measured in meter and t in second

The correct option is B 12 s x = 23 t^2 16t + 2 v=dx/dt v = 43 t 16 when the body comes to rest : #160; v=0 #160; #160; ...

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Standard XII

Mathematics

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The displacement $x$ of a body varies with time $t$ as $x = \frac{2}{3} t^{2} - 16 t + 2$ . In what time that body comes to rest? (x is measured in meter and t in second)

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Solution

The correct option is B $12 s$
$x = \frac{2}{3} t^{2} - 16 t + 2$
$v = \frac{d x}{d t}$
$v = \frac{4}{3} t - 16$
when the body comes to rest : $v = 0$
$\frac{4}{3} t - 16 = 0$
$t = 12 s$

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The displacement x of a body varies with time t as x=23t2−16t+2. In what time that body comes to rest? (x is measured in meter and t in second)

The correct option is B 12 sx=23t2−16t+2v=dxdtv=43t−16when the body comes to rest : v=0 43t−16=0 t=12s

The displacement $x$ of a body varies with time $t$ as $x = \frac{2}{3} t^{2} - 16 t + 2$ . In what time that body comes to rest? (x is measured in meter and t in second)

The correct option is B $12 s$
$x = \frac{2}{3} t^{2} - 16 t + 2$
$v = \frac{d x}{d t}$
$v = \frac{4}{3} t - 16$
when the body comes to rest : $v = 0$
$\frac{4}{3} t - 16 = 0$
$t = 12 s$