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Byju's Answer
Standard XII
Physics
Vectors and Its Types
The displacem...
Question
The displacement x of a partical along x-axis is given by x=3 +8t +7t (sq) obtain it's velocity and acceleration at t =2s
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Solution
x =x=3 +8t +7t^2
Assuming that you have the basic knowledge of differentiation
Velocity = dx/dt = 8 + 7*2*t
At t=2sec
Velocity = 8+7*2*2 = 36m/s
Acceleration = dv/dt = 14m/s2 constant for all t
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