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Question

The displacement x of a particle along a straight line at time t is given by x=a0+a1t+a2t3. The acceleration a of the particle at time t=5 is

A
15a2
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B
30a2
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C
a1+30a2
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D
6a2
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Solution

The correct option is B 30a2
Instantaneous acceleration is given by, a=dvdt and v=dxdtv=d(a0+a1t+a2t3)dt=a1+3a2t2
a=d(a1+3a2t2)dta=6a2 t
Hence, acceleration a at t=5 a=6a2×5=30a2

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