The displacement x of a particle along a straight line at time t is given by x=a0+a1t+a2t3. The acceleration a of the particle at time t=5 is
A
15a2
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B
30a2
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C
a1+30a2
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D
6a2
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Solution
The correct option is B30a2 Instantaneous acceleration is given by, a=dvdt and v=dxdt⇒v=d(a0+a1t+a2t3)dt=a1+3a2t2 ∴a=d(a1+3a2t2)dt⇒a=6a2t
Hence, acceleration a at t=5⇒a=6a2×5=30a2