The displacement x of a particle along a straight line at time t is given by x=a0−a1t+a2t2. The acceleration of the particle is
A
a0
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B
a1
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C
2a2
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D
a2
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Solution
The correct option is C2a2 Acceleration of the particle is given by a(t)=d2xdt2=d(dxdt)dt So, dxdt=d(a0−a1t+a2t2)dt=−a1+2a2t Thus, a(t)=d2xdt2=d(−a1+2a2t)dt ⇒a(t)=2a2, which is constant.