Question

# The displacement x of a particle along a straight line at time t is given by x=a0−a1t+a2t2. The acceleration of the particle isa0a12a2a2

Solution

## The correct option is C 2a2Acceleration of the particle is given by a(t)=d2xdt2=d(dxdt)dt So, dxdt=d(a0−a1t+a2t2)dt=−a1+2a2t Thus, a(t)=d2xdt2=d(−a1+2a2t)dt ⇒ a(t)=2a2, which is constant.

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