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Question

The displacement x of a particle along a straight line at time t is given by x=a0a1t+a2t2. The acceleration of the particle is
  1. a0
  2. a1
  3. 2a2
  4. a2


Solution

The correct option is C 2a2
Acceleration of the particle is given by
a(t)=d2xdt2=d(dxdt)dt
So, dxdt=d(a0a1t+a2t2)dt=a1+2a2t
Thus, a(t)=d2xdt2=d(a1+2a2t)dt
 a(t)=2a2, which is constant.

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