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Question

The displacement (x) of a particle as a function of time (t) is given by
X = a sin (bt + c)
Where a, b and c are constants of motion. Choose the correct statement(s) from the following

A
The motion repeats itself in a time interval 2πb
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B
The energy of the particle remains constant
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C
The velocity of the particle is zero at x = ± a
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D
The acceleration of the particle is zero at x =± a
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Solution

The correct option is A The motion repeats itself in a time interval 2πb
The motion of the particle is simple harmonic. The displacement at time t is X = a sin (bt+c) Displacement at time (t+2πb) is x(at t+2πb)=a sin[b(t+2πb)+c] =a sin(bt+c+2π) =a sin(bt+c) =x at time t Hence statement (a) is correct. Statement (b) is also correct since the same displacement is recovered after a time interval of 2πb .Statement (c) is correct because the velocity is zero when the displacement = ± the amplitude, i.e. at the extreme ends of the motion. Statement (d)is incorrect, the acceleration is maximum (in magnitude) at x = ± a.

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