You visited us 1 times! Enjoying our articles? Unlock Full Access!

Finding Average Velocity

The displacem...

Question

The displacement x of a particle moving along the x-axis at time t is given by $x = 2 t^{2} + 6 t$ .The velocity at any time t is

\frac{4 t + 6}{x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2 t - x}{x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4 t + 6

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{2 t + 3}{x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $4 t + 6$
The displacement $x$ of a particle moving along the x-axis at time $t$ is given by
$x = 2 t^{2} + 6 t$
The velocity at any time is $v = \frac{d x}{d t}$
$v = \frac{d (2 t^{2} + 6 t)}{d t}$
$v = 4 t + 6$
The correct option is C.

Suggest Corrections

Similar questions

x (t) = 2 t^{3} - 3 t^{2} + 4 t

x = 4 t + 4 t^{2}

y = 5 t

t = 1

x = 2 t^{2}

y = t^{2} - 4 t

z = 3 t

x

t

x = \frac{a_{1}}{2} t + \frac{a_{2}}{3} t^{2}

x

t

x = 2 t^{3} - 12 t^{2} + 6 t + 8

x

t

Join BYJU'S Learning Program