104
Question
The displacement x of a particle moving in one dimension is related to time t by the equation t=√x+3 where x is in metres and t in seconds. The displacement of the particle when its velocity is zero.Please,Define the Whole Process of How to Differentiate it?(Step by Step Please)
The displacement x of a particle moving in one dimension is related to time t by the equation t=√x+3 where x is in metres and t in seconds. The displacement of the particle when its velocity is zero.Please,Define the Whole Process of How to Differentiate it?(Step by Step Please)
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Solution
t = √x + 3
on squaring
√x = t - 3
x = t2 - 6t + 9
Now differentiate x wrt t, dx/dt is velocity
dx/dt = 2t - 6
velocity v = 2t - 6
v = 0
2t - 6 = 0
that gives t = 3
at t = 3 ,
x = 3 - 3
0 displacement
t = √x + 3
on squaring
√x = t - 3
x = t2 - 6t + 9
Now differentiate x wrt t, dx/dt is velocity
dx/dt = 2t - 6
velocity v = 2t - 6
v = 0
2t - 6 = 0
that gives t = 3
at t = 3 ,
x = 3 - 3
0 displacement
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