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Question

The displacement x of a particle of mass m kg moving in one dimension is related to the time t by the equation t=4x+3 where x is in metre and t is in second. The work done by the force in the first six seconds in joules is

A
0 J
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B
3 J
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C
6 J
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D
9 J
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Solution

The correct option is A 0 J
Given,
t=4x+3x=14(t3)
v=dxdt=14(1)=14 m/s
So, the velocity is constant.

According to Work energy theorem,
Wnet=ΔKE=0

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